Kinetic Bombardment by tungsten rods yields a maximum of the equivalent to what would be a .12 kt explosion of TNT, or a 30m radius in damage. Bombardment of these weapons would most certainly not decimate the ground theatre, nor would it provide mass-scaled damage.Draco Vereen said:[member="Silara Kuhn"]
Kinetic Bombardment from this sub http://starwarsrp.net/topic/48375-hepf-1-saint/
As a tungsten rod, there is no fireball effect. It is a 30 meter crater, not a fireball the size of 30 meters, as this is a nuclear device simulator.Zhol Kash Dinora said:Fireball radius: 30 m (3,620 m²) Maximum size of the nuclear fireball; relevance to lived effects depends on height of detonation. If it touches the ground, the amount of radioactive fallout is significantly increased.
As with the previous quote, this is not applicable as there is no nuclear and radioactive substances being dropped.Zhol Kash Dinora said:Thermal radiation radius (3rd degree burns): 250 m (0.19 km²) Third degree burns extend throughout the layers of skin, and are often painless because they destroy the pain nerves. They can cause severe scarring or disablement, and can require amputation. 100% probability for 3rd degree burns at this yield is 6.3 cal/cm2.
Both of these have to reach out of the crater, which removes roughly 16 meters of vertical (technically 30 meters of climb) from the range.Zhol Kash Dinora said:Air blast radius (20 psi): 110 m (0.04 km²) At 20 psi overpressure, heavily built concrete buildings are severely damaged or demolished; fatalities approach 100%. Air blast radius (5 psi): 230 m (0.16 km²) At 5 psi overpressure, most residential buildings collapse, injuries are universal, fatalities are widespread.
In the case of the system mentioned in the 2003 Air Force report above, a 6.1 m × 0.3 m tungsten cylinder impacting at Mach 10 has a kinetic energy equivalent to approximately 11.5 tons of TNT (or 7.2 tons of dynamite). The mass of such a cylinder is itself greater than 9 tons, so it is clear that the practical applications of such a system are limited to those situations where its other characteristics provide a decisive advantage—a conventional bomb/warhead of similar weight to the tungsten rod, delivered by conventional means, provides similar destructive capability and is a far more practical method
Are we talking about Rods from God?Draco Vereen said:Though from a physics perspective, could a rod that small even survive re-entry? And a much larger one only had a yield of 11.5 tons to TNT. (9 tons of tungsten carbide) and these are smaller than 10 starfighter sized warheads. They aren't going to be more than 100 kilograms each. So these are completely impractical and basically useless at that size.
Yes thats their nickname. Sorry I think its cool someone remembered that.Hion the Herglic said:Rods from God?
Then, based on my talks with Rhys who has an astrophysics doctorate, we calculated what kind of damage I am potentially dealing with here. He says that to reach terminal velocity after reviewing the sub and the kinetic bombardment theory that you require at least 20KM to reach terminal velocity -- which i went cool.
Then we determined the amount of damage per tungson rod ( there was no actual reference to a size, so we went by the following measurements of a standard rod of around 7 tonnes, 2m rod, 50cm across.)
Assuming Earth gravity and atmosphere to make this easier ( as every planet is different). That is 30 tonnes 600m/s and after Rhys calculated theoretical max, came to 15GJ or (0.003ktn warhead). Which is a long way from a nuclear strike, and is more in the regions of a normal missile warhead from my Aviation Ordnance background.
So -- In summary, take an extra post to get there and given Rhy's calculations on height required for terminal velocity and the amount of actual kinetic energy and my defenses on the breeding grounds, I know exactly what the damage output will be.